How to clone request's client to remote server and return result original request to client

bientd88 · 2016-07-05T15:59:05+00:00

Hi,I am using balancer_by_lua and ngx.balancer.set_current_peer to dynamically proxy to different upstreams based on a previous lookup.Does the keepalive con...

How to clone request's client to remote server and return result original request to client

bientd88

Hi everyone,

I'm used http.resty module to mirror client request for my web server 192.168.4.13 to 192.168.10.51. After cloning I still want to return results to users early on. Now I have to clone the request, but not know how to return the original results.

Help me! my config below:

location / {
    root html;
    index index.html;
    resolver 8.8.8.8; # use Google's open DNS server for an example

    content_by_lua '
        local uri = ngx.var.request_uri
        local url_mirror = "http://192.168.10.51"

        local http = require "resty.http"
        local httpc = http.new()
        httpc:set_timeout(100)
        local res, err = httpc:request_uri(url_mirror, {
            method = "POST",
            body = "content log here",    -- content TIME, IP_CLIENT, URI
            headers = {
                ["Content-Type"] = "application/x-www-form-urlencoded",
                ["User-Agent"] = "kma-VN"
            }
        })

        if not res then
            ngx.say("failed to request ", err)
            httpc:close()
        else
            httpc:close()
        end
    ';
}